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Question

A dissipation-less transmission line whose characteristic impedance is 200 ohms is connected to a load of $(100+j100)$ ohms. The frequency is 300 MHz. If the length of the line is 25 cm, then the input impedance of the line is

The correct answer is
282.80 ohms

Transmission Line Input Impedance Calculation

This problem involves finding the input impedance ($Z_{in}$) of a dissipation-less transmission line given its characteristic impedance ($Z_0$), load impedance ($Z_L$), frequency ($f$), and length ($l$). The result needs to match one of the provided options, which appear to represent the magnitude of the impedance.

Given Parameters

  • Characteristic Impedance: $Z_0 = 200 \, \Omega$
  • Load Impedance: $Z_L = (100 + j100) \, \Omega$
  • Frequency: $f = 300 \, \text{MHz} = 3 \times 10^8 \, \text{Hz}$
  • Line Length: $l = 25 \, \text{cm} = 0.25 \, \text{m}$
  • Speed of Light (in assumed lossless medium): $c \approx 3 \times 10^8 \, \text{m/s}$

Calculate Wavelength and Electrical Length

  1. Calculate the phase constant ($\beta$): $ \beta = \frac{2 \pi f}{c} = \frac{2 \pi (3 \times 10^8 \, \text{Hz})}{3 \times 10^8 \, \text{m/s}} = 2 \pi \, \text{rad/m} $
  2. Calculate the electrical length ($\beta l$): $ \beta l = (2 \pi \, \text{rad/m}) \times (0.25 \, \text{m}) = \frac{\pi}{2} \, \text{rad} $
  3. Interpretation: An electrical length of $\frac{\pi}{2}$ radians corresponds to a quarter of a wavelength ($\lambda/4$).

Input Impedance Formula for Quarter-Wave Line

For a dissipation-less transmission line with length $l = \lambda/4$, the input impedance can be calculated using the relationship:

$ Z_{in} = \frac{Z_0^2}{Z_L} $

This formula arises from the general transmission line formula when $\tan(\beta l)$ approaches infinity.

Calculate Input Impedance ($Z_{in}$)

  1. Substitute the values into the formula: $ Z_{in} = \frac{(200 \, \Omega)^2}{(100 + j100) \, \Omega} = \frac{40000}{100(1 + j)} \, \Omega $
  2. Simplify the expression: $ Z_{in} = \frac{400}{1 + j} \, \Omega $
  3. Rationalize the denominator: $ Z_{in} = \frac{400}{1 + j} \times \frac{1 - j}{1 - j} \, \Omega = \frac{400(1 - j)}{1^2 - (j)^2} \, \Omega = \frac{400(1 - j)}{1 - (-1)} \, \Omega = \frac{400(1 - j)}{2} \, \Omega $
  4. Final complex impedance: $ Z_{in} = 200(1 - j) \, \Omega = (200 - j200) \, \Omega $

Determine Magnitude for Option Matching

The options provided are real numbers, suggesting the magnitude of the input impedance is required.

  • Calculate the magnitude: $ |Z_{in}| = |200 - j200| \, \Omega = \sqrt{200^2 + (-200)^2} \, \Omega $ $ |Z_{in}| = \sqrt{40000 + 40000} \, \Omega = \sqrt{80000} \, \Omega $ $ |Z_{in}| = \sqrt{40000 \times 2} \, \Omega = 200\sqrt{2} \, \Omega \approx 282.84 \, \Omega $

The calculated magnitude, approximately 282.84 ohms, closely matches Option B.

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Important Questions from Transmission Lines

  1. A characteristic impedance does NOT satisfy which of the following statements?

  2. The dielectric constant of the material used in a transmission line is 2. What is the velocity factor of this line if its characteristic impedance is 300 Ω?

  3. What is the VSWR when feeding an RF signal to a 55 Ω load through a coaxial cable of characteristic impedance 50 Ω?

  4. A transmission line of \(50{\rm{\;\Omega }}\) characteristic impedance is terminated with a \(\rm 100 \ Ω\) resistance. The minimum impedance measured on the line is equal to

  5. Twisting of live and return lines in long signal lines is done to reduce the effect of

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