A dipole carries RMS current of about 300 A across the radiation resistance 2 Ω. What would be the power radiated by an antenna?
180 kW
P_{rad} (in kW) = (180000 W)/(1000) P_{rad} (in kW) = 180 kW So, the power radiated by the antenna is 180 kW. Parameter Value Unit RMS Current (I_{rms}) 300 A Radiation Resistance (R_{rad}) 2 \Omega Calculated Power Radiated (P_{rad}) 180000 W Calculated Power Radiated (P_{rad}) 180 kW Conclusion on Antenna Power Calculation Based on the given RMS current of 300 A and a radiation resistance of 2 \Omega, the power radiated by the dipole antenna is calculated to be 180 kW.
Important Questions from Basics of Antenna
Arrange the following antennas in ascending order of their radiation resistance.
A. Short dipole (L = \(\frac{\lambda}{10}\) )(I av = l o)
B. Short dipole (L= \(\frac{\lambda}{10}\) )( I av = l o/2)
C. Linear \(\frac{\lambda}{2}\) dipole (sinusoidal current distribution)
D. Small Loop (square loop) single turn of(L = \(\frac{\lambda}{10}\) )
Choose the correct answer from the options given below
If the frequency of the signal is 1 MHz, the minimum height of the transmitting antenna should be:
The Antenna employed in Television receivers
Which of the following is NOT true with respect to antennas?
An instrument to check whether RF power in the transmission line is transferred to the antenna is:
