A desert cooler having a cooling efficiency of 70% reduces the temperature of ambient air from 37°C to 30°C. The Wet Bulb Temperature (WBT) of air is
27 °C
This problem involves understanding the operation of a desert cooler, also known as an evaporative cooler, and its cooling efficiency. Desert coolers cool air by evaporating water, which reduces the air's dry bulb temperature (DBT) and increases its humidity. The theoretical limit of cooling by evaporation is the wet bulb temperature (WBT) of the incoming air.
The cooling efficiency ($\eta$) of an evaporative cooler is given by the formula:
$$\eta = \frac{DBT_{in} - DBT_{out}}{DBT_{in} - WBT_{in}}$$
Where:
We are given the following information:
We need to find the initial Wet Bulb Temperature ($WBT_{in}$).
Substitute the given values into the efficiency formula:
$$0.70 = \frac{37°C - 30°C}{37°C - WBT_{in}}$$
1. Calculate the temperature drop in the numerator:
$$37°C - 30°C = 7°C$$
The equation becomes:
$$0.70 = \frac{7°C}{37°C - WBT_{in}}$$
2. Rearrange the equation to solve for the denominator ($37°C - WBT_{in}$):
$$37°C - WBT_{in} = \frac{7°C}{0.70}$$
3. Calculate the value on the right side:
$$\frac{7}{0.70} = 10$$
So, the equation is now:
$$37°C - WBT_{in} = 10°C$$
4. Solve for $WBT_{in}$:
$$WBT_{in} = 37°C - 10°C$$
$$WBT_{in} = 27°C$$
The Wet Bulb Temperature of the air entering the desert cooler is 27°C.
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