A current of 0.6 A is drawn by an electric bulb for 10 minutes. Which one of the following is the amount of electric charge that flows through the circuit?
360 C
The problem asks us to find the amount of electric charge that flows through an electric bulb given the current drawn and the time duration.
Electric current (\(I\)) is defined as the rate of flow of electric charge (\(Q\)) through a conductor. The formula connecting these quantities is:
\(I = \frac{Q}{t}\)
where:
From this formula, we can find the charge \(Q\) by rearranging it:
\(Q = I \times t\)
We are given the following values:
The standard unit for time in the formula \(Q = I \times t\) is seconds. The given time is in minutes, so we need to convert it to seconds. There are 60 seconds in 1 minute.
\(t = 10 \text{ minutes} \times 60 \frac{\text{seconds}}{\text{minute}}\)
\(t = 600 \text{ seconds}\)
Now we can use the formula \(Q = I \times t\) with the converted time in seconds.
\(Q = 0.6 \text{ A} \times 600 \text{ s}\)
\(Q = 360 \text{ C}\)
Therefore, the amount of electric charge that flows through the circuit is 360 Coulombs.
Let's compare our calculated charge with the given options:
| Option | Value | Matches Calculation? |
|---|---|---|
| 1 | 6 C | No |
| 2 | 0.6 C | No |
| 3 | 360 C | Yes |
| 4 | 36 C | No |
Our calculated value of 360 C matches Option 3.
| Quantity | Symbol | SI Unit | Formula | Relationship |
|---|---|---|---|---|
| Electric Current | \(I\) | Ampere (A) | \(I = Q/t\) | Rate of flow of charge |
| Electric Charge | \(Q\) | Coulomb (C) | \(Q = I \times t\) | Fundamental property, flows as current |
| Time | \(t\) | Second (s) | \(t = Q/I\) | Duration of charge flow |
Electric charge is a fundamental property of matter. It can be positive or negative. The smallest unit of free charge is the charge of an electron or a proton. The SI unit for charge is the Coulomb (C).
Electric current is the flow of electric charge through a material. It is measured in Amperes (A). One Ampere is defined as the flow of one Coulomb of charge per second (\(1 \text{ A} = 1 \text{ C/s}\)). Current flows from a region of higher potential to a region of lower potential in a circuit.
In the standard SI system of units, the unit of current (Ampere) is defined based on Coulombs per second. Therefore, when using the formula \(Q = I \times t\), time must be in seconds to get the charge in Coulombs.
Electric current is what powers our devices, from simple light bulbs to complex computers. When you turn on a light bulb, electric charge flows through the filament, causing it to heat up and produce light. The amount of charge flowing depends on how much current the bulb draws and for how long it is on, just like in this problem.
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