A couple produces _____________ type of motion.
Rotational
Let's analyse the type of motion produced by a concept in mechanics known as a couple. A couple is a pair of forces equal in magnitude, opposite in direction, and displaced by a perpendicular distance or moment arm. These forces do not act along the same line, which is crucial to the effect they produce.
A couple consists of two forces, say \(F_1\) and \(F_2\), such that:
This perpendicular distance is called the arm of the couple, denoted by \(d\). The product of the magnitude of one force and the perpendicular distance between them is called the moment of the couple, \(M = F \times d\).
When a force acts on an object, it can cause two types of motion: translation (movement from one point to another) and rotation (movement around an axis).
Translatory motion occurs when the net force acting on an object is non-zero. The object's center of mass moves in the direction of the net force, as described by Newton's second law, \(\Sigma \vec{F} = m\vec{a}\).
For a couple, the net force is the vector sum of the two forces:
\(\Sigma \vec{F} = \vec{F_1} + \vec{F_2}\)
Since \(\vec{F_1}\) and \(\vec{F_2}\) are equal in magnitude and opposite in direction, their vector sum is zero:
\(\Sigma \vec{F} = F \hat{i} + (-F) \hat{i} = \vec{0}\) (assuming forces are along the x-axis for simplicity)
Because the net force is zero, a couple does not cause any net translatory acceleration of the center of mass. Therefore, a couple alone cannot produce translatory motion from rest, nor can it change the velocity of an object undergoing translation.
Rotational motion occurs when a net torque acts on an object. Torque is the tendency of a force to rotate an object about an axis or a point. For a single force, torque (\(\tau\)) is calculated as the product of the force magnitude and the perpendicular distance from the pivot point to the line of action of the force (\(\tau = F \times r_\perp\)). For multiple forces, it is the sum of individual torques.
For a couple, both forces contribute to the total torque. Let's consider a point O (which can be anywhere). Force \(F_1\) is at a distance \(r_1\) from O, and \(F_2\) is at a distance \(r_2\) from O. The lines of action of \(F_1\) and \(F_2\) are separated by the distance \(d\), the arm of the couple.
The total torque about point O is the sum of the torques due to \(F_1\) and \(F_2\). The key characteristic of a couple is that its moment (torque) is the same about any point in the plane of the couple.
Let's illustrate with a simple example:
| Force | Magnitude | Direction | Line of Action | Torque Contribution (about any point P) |
|---|---|---|---|---|
| \(F_1\) | \(F\) | Upward (\(\uparrow\)) | At position x | Tends to rotate clockwise (or counter-clockwise depending on P) |
| \(F_2\) | \(F\) | Downward (\(\downarrow\)) | At position x+d | Tends to rotate clockwise (or counter-clockwise depending on P) |
The total torque generated by the couple is \(M = F \times d\). This net torque causes angular acceleration according to \(\Sigma \tau = I\alpha\), where \(I\) is the moment of inertia and \(\alpha\) is the angular acceleration.
Since the net torque is non-zero, a couple produces rotational motion. The object subjected to a couple will rotate about an axis perpendicular to the plane of the couple. The axis of rotation passes through the center of mass if no other forces are acting.
Based on the analysis:
Therefore, a couple produces pure rotational motion. There is no translation of the center of mass caused solely by a couple.
Let's examine the given options:
Thus, a couple produces rotational motion.
| Type of Motion | Caused By | Effect on Center of Mass | Example |
|---|---|---|---|
| Translatory | Net Force (\(\Sigma \vec{F} \neq \vec{0}\)) | Translates (\(\vec{a} \neq \vec{0}\)) | Pushing a box across the floor |
| Rotational | Net Torque (\(\Sigma \tau \neq 0\)) | Can remain stationary or translate, but the object rotates about an axis (\(\alpha \neq 0\)) | Turning a steering wheel with both hands (forms a couple) |
| Combined | Net Force (\(\Sigma \vec{F} \neq \vec{0}\)) AND Net Torque (\(\Sigma \tau \neq 0\)) | Translates AND Rotates | Rolling ball, throwing a spinning object |
| Reciprocating | Varying forces causing back-and-forth translation | Moves back and forth along a line | Piston in an engine |
A couple is often represented by its moment vector, whose magnitude is \(M = Fd\) and direction is perpendicular to the plane of the couple, following the right-hand rule. The effect of a couple on a rigid body is independent of the point of application in the body; only the moment of the couple matters. This means that any two couples with the same moment vector are equivalent in terms of their effect on a rigid body.
Understanding couples is fundamental in mechanics, especially when dealing with the rotation of rigid bodies, structures, and machines.
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