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Question

A couple produces _____________ type of motion.

The correct answer is

Rotational

Understanding the Motion Produced by a Couple

Let's analyse the type of motion produced by a concept in mechanics known as a couple. A couple is a pair of forces equal in magnitude, opposite in direction, and displaced by a perpendicular distance or moment arm. These forces do not act along the same line, which is crucial to the effect they produce.

What is a Couple?

A couple consists of two forces, say \(F_1\) and \(F_2\), such that:

  • \(|F_1| = |F_2|\) (Equal magnitude)
  • \(F_1\) and \(F_2\) are opposite in direction.
  • \(F_1\) and \(F_2\) are parallel to each other but not collinear (they have a perpendicular distance between their lines of action).

This perpendicular distance is called the arm of the couple, denoted by \(d\). The product of the magnitude of one force and the perpendicular distance between them is called the moment of the couple, \(M = F \times d\).

Analysing the Effect of a Couple on Motion

When a force acts on an object, it can cause two types of motion: translation (movement from one point to another) and rotation (movement around an axis).

Translatory Motion

Translatory motion occurs when the net force acting on an object is non-zero. The object's center of mass moves in the direction of the net force, as described by Newton's second law, \(\Sigma \vec{F} = m\vec{a}\).

For a couple, the net force is the vector sum of the two forces:

\(\Sigma \vec{F} = \vec{F_1} + \vec{F_2}\)

Since \(\vec{F_1}\) and \(\vec{F_2}\) are equal in magnitude and opposite in direction, their vector sum is zero:

\(\Sigma \vec{F} = F \hat{i} + (-F) \hat{i} = \vec{0}\) (assuming forces are along the x-axis for simplicity)

Because the net force is zero, a couple does not cause any net translatory acceleration of the center of mass. Therefore, a couple alone cannot produce translatory motion from rest, nor can it change the velocity of an object undergoing translation.

Rotational Motion

Rotational motion occurs when a net torque acts on an object. Torque is the tendency of a force to rotate an object about an axis or a point. For a single force, torque (\(\tau\)) is calculated as the product of the force magnitude and the perpendicular distance from the pivot point to the line of action of the force (\(\tau = F \times r_\perp\)). For multiple forces, it is the sum of individual torques.

For a couple, both forces contribute to the total torque. Let's consider a point O (which can be anywhere). Force \(F_1\) is at a distance \(r_1\) from O, and \(F_2\) is at a distance \(r_2\) from O. The lines of action of \(F_1\) and \(F_2\) are separated by the distance \(d\), the arm of the couple.

The total torque about point O is the sum of the torques due to \(F_1\) and \(F_2\). The key characteristic of a couple is that its moment (torque) is the same about any point in the plane of the couple.

Let's illustrate with a simple example:

Force Magnitude Direction Line of Action Torque Contribution (about any point P)
\(F_1\) \(F\) Upward (\(\uparrow\)) At position x Tends to rotate clockwise (or counter-clockwise depending on P)
\(F_2\) \(F\) Downward (\(\downarrow\)) At position x+d Tends to rotate clockwise (or counter-clockwise depending on P)

The total torque generated by the couple is \(M = F \times d\). This net torque causes angular acceleration according to \(\Sigma \tau = I\alpha\), where \(I\) is the moment of inertia and \(\alpha\) is the angular acceleration.

Since the net torque is non-zero, a couple produces rotational motion. The object subjected to a couple will rotate about an axis perpendicular to the plane of the couple. The axis of rotation passes through the center of mass if no other forces are acting.

Conclusion: Type of Motion

Based on the analysis:

  • Net force produced by a couple is zero (\(\Sigma \vec{F} = \vec{0}\)). This means no translatory acceleration.
  • Net torque produced by a couple is non-zero (\(\Sigma \tau = F \times d\)). This means angular acceleration.

Therefore, a couple produces pure rotational motion. There is no translation of the center of mass caused solely by a couple.

Let's examine the given options:

  1. Reciprocating: This is back and forth translatory motion, not produced by a couple.
  2. Rotational: This is motion about an axis, consistent with the effect of a torque produced by a couple.
  3. Combination of translatory and rotational: This happens when a net force *and* a net torque are present, which is not the case for a pure couple.
  4. Translatory: This requires a net force, which a couple does not provide.

Thus, a couple produces rotational motion.

Revision Table: Motion Types

Type of Motion Caused By Effect on Center of Mass Example
Translatory Net Force (\(\Sigma \vec{F} \neq \vec{0}\)) Translates (\(\vec{a} \neq \vec{0}\)) Pushing a box across the floor
Rotational Net Torque (\(\Sigma \tau \neq 0\)) Can remain stationary or translate, but the object rotates about an axis (\(\alpha \neq 0\)) Turning a steering wheel with both hands (forms a couple)
Combined Net Force (\(\Sigma \vec{F} \neq \vec{0}\)) AND Net Torque (\(\Sigma \tau \neq 0\)) Translates AND Rotates Rolling ball, throwing a spinning object
Reciprocating Varying forces causing back-and-forth translation Moves back and forth along a line Piston in an engine

Additional Information on Couples

A couple is often represented by its moment vector, whose magnitude is \(M = Fd\) and direction is perpendicular to the plane of the couple, following the right-hand rule. The effect of a couple on a rigid body is independent of the point of application in the body; only the moment of the couple matters. This means that any two couples with the same moment vector are equivalent in terms of their effect on a rigid body.

Understanding couples is fundamental in mechanics, especially when dealing with the rotation of rigid bodies, structures, and machines.

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Important Questions from Law of Motion

  1. A crane lifts a mass of 200 kg from rest and it attains an upward velocity of 3 m/s in 2 s uniformly. The tension in the supporting cable is

  2. An example of rotational motion is

  3. Impulse gives a measure of the product of -

  4. If 'F' is the force acting on the body, 'm' is the mass of the body and 'a' is the acceleration of the body, then which of the following is true according to Newton's second law of motion?

  5. The rate of change of momentum of an object is -

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