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Question

A constant force F acts on a box of mass 10 kg for a duration of 2 s. It increases the object’s velocity from 6 m/s to 10 m/s. The magnitude of the applied force F is:

The correct answer is

20 N

Using Newton’s Second Law: F = ma
First, calculate acceleration: a = (v - u) / t = (10 - 6) / 2 = 4 m/s²
Then, F = 10 kg × 4 m/s² = 20 N.

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