A cone and a cylinder have same height and the radius of the cone is twice of the radius of the cylinder. What is the ratio of the volume of the cone to that of the cylinder?
4 : 3
This problem asks us to find the ratio of the volume of a cone to the volume of a cylinder, given that they have the same height and a specific relationship between their radii.
Let's break down the problem step-by-step:
The formula for the volume of a cone is:
\(V_{k} = \frac{1}{3} \pi r_{k}^2 h\)
The formula for the volume of a cylinder is:
\(V_{c} = \pi r_{c}^2 h\)
Now, we substitute the relationship between the radii (\(r_{k} = 2r_{c}\)) into the volume formula for the cone:
\(V_{k} = \frac{1}{3} \pi (2r_{c})^2 h\)
Simplify the term \((2r_{c})^2\):
\((2r_{c})^2 = 2^2 \times r_{c}^2 = 4r_{c}^2\)
Substitute this back into the cone volume formula:
\(V_{k} = \frac{1}{3} \pi (4r_{c}^2) h\)
\(V_{k} = \frac{4}{3} \pi r_{c}^2 h\)
The volume of the cylinder is simply:
\(V_{c} = \pi r_{c}^2 h\)
The question asks for the ratio of the volume of the cone to that of the cylinder, which is \(V_{k} : V_{c}\) or \(\frac{V_{k}}{V_{c}}\).
Let's calculate the ratio:
\(\frac{V_{k}}{V_{c}} = \frac{\frac{4}{3} \pi r_{c}^2 h}{\pi r_{c}^2 h}\)
We can cancel out the common terms \(\pi r_{c}^2 h\) from the numerator and the denominator, provided that \(\pi r_{c}^2 h \neq 0\). Since radius and height are dimensions of physical objects, they are positive, so this condition is met.
\(\frac{V_{k}}{V_{c}} = \frac{\frac{4}{3}}{1}\)
\(\frac{V_{k}}{V_{c}} = \frac{4}{3}\)
So, the ratio of the volume of the cone to that of the cylinder is 4 : 3.
Let's check the given options:
| Option | Ratio |
|---|---|
| 1 | 2 : 5 |
| 2 | 4 : 5 |
| 3 | 3 : 2 |
| 4 | 4 : 3 |
Our calculated ratio is 4 : 3, which matches Option 4.
Let \(h\) be the height and \(r_{c}\) be the radius of the cylinder. The radius of the cone is \(r_{k} = 2r_{c}\). Both have height \(h\).
Volume of cone, \(V_{k} = \frac{1}{3} \pi r_{k}^2 h = \frac{1}{3} \pi (2r_{c})^2 h = \frac{1}{3} \pi (4r_{c}^2) h = \frac{4}{3} \pi r_{c}^2 h\).
Volume of cylinder, \(V_{c} = \pi r_{c}^2 h\).
Ratio \(V_{k} : V_{c} = \frac{\frac{4}{3} \pi r_{c}^2 h}{\pi r_{c}^2 h} = \frac{4}{3}\).
The ratio is 4 : 3.
| Shape | Height | Radius | Volume Formula | Volume with \(h\) and \(r_{c}\) |
|---|---|---|---|---|
| Cylinder | \(h\) | \(r_{c}\) | \(V_{c} = \pi r_{c}^2 h\) | \(\pi r_{c}^2 h\) |
| Cone | \(h\) | \(r_{k} = 2r_{c}\) | \(V_{k} = \frac{1}{3} \pi r_{k}^2 h\) | \(\frac{1}{3} \pi (2r_{c})^2 h = \frac{4}{3} \pi r_{c}^2 h\) |
Understanding the formulas for the volumes of basic 3D shapes like cones, cylinders, and spheres is crucial in geometry. Problems often involve comparing the volumes of these shapes under specific conditions, such as having equal heights, equal radii, or related dimensions.
Key concepts:
When tackling ratio problems involving geometric shapes, always:
This structured approach helps in solving such problems systematically and accurately.
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