A clock is set to the right time at 4:00 AM on Thursday. If it gains 20 seconds in every 3 hours, then what is the time shown on the clock at 8:30 PM on Friday night?
8 hours 34 minutes 30 seconds PM
This question involves a clock that is not perfectly accurate; it gains time at a constant rate. We are given the starting time when it was correct, the rate at which it gains time, and the target time we need to find what the clock shows.
The key steps to solve this kind of problem are:
The clock was set correctly at 4:00 AM on Thursday.
We want to find the time shown at 8:30 PM on Friday night.
So, the total time from Friday 4:00 AM to 8:30 PM is $8 \text{ hours} + 8 \text{ hours} + 30 \text{ minutes} = 16 \text{ hours } 30 \text{ minutes}$.
Total elapsed time from Thursday 4:00 AM to Friday 8:30 PM is:
$24 \text{ hours } + 16 \text{ hours } 30 \text{ minutes} = 40 \text{ hours } 30 \text{ minutes}$.
To make calculations easier, we can convert 30 minutes into hours: $30 \text{ minutes} = \frac{30}{60} \text{ hours} = 0.5 \text{ hours}$.
Total elapsed time is $40.5$ hours.
The clock gains 20 seconds in every 3 hours.
We need to find the total gain in 40.5 hours.
Number of 3-hour intervals in 40.5 hours = $\frac{40.5 \text{ hours}}{3 \text{ hours/interval}}$
Number of intervals = $13.5$ intervals.
Since the clock gains 20 seconds per 3-hour interval, the total gain is:
Total gain = Number of intervals $\times$ Gain per interval
Total gain = $13.5 \times 20 \text{ seconds}$
Total gain = $270 \text{ seconds}$.
We know that 60 seconds make 1 minute.
To convert 270 seconds into minutes and seconds, we divide 270 by 60:
$270 \div 60 = 4$ with a remainder of $30$.
So, 270 seconds is equal to 4 minutes and 30 seconds.
The correct time at the end of the elapsed duration is 8:30 PM on Friday night.
The clock has gained 4 minutes and 30 seconds over this period.
The time shown on the clock will be the correct time plus the gain.
Time shown = Correct time + Total gain
Correct time = 8:30 PM
Total gain = 4 minutes 30 seconds
Time shown = 8 hours 30 minutes 0 seconds PM + 0 hours 4 minutes 30 seconds
Time shown = 8 hours 34 minutes 30 seconds PM.
Let's look at the given options:
Our calculated time is 8 hours 34 minutes 30 seconds PM, which matches one of the options.
| Description | Value |
|---|---|
| Start Time (Correct) | Thursday, 4:00 AM |
| End Time (Correct) | Friday, 8:30 PM |
| Total Elapsed Time | 40 hours 30 minutes (40.5 hours) |
| Clock Gain Rate | 20 seconds per 3 hours |
| Number of 3-hour intervals | 40.5 / 3 = 13.5 |
| Total Gain in Seconds | 13.5 × 20 = 270 seconds |
| Total Gain in Minutes/Seconds | 270 seconds = 4 minutes 30 seconds |
| Time Shown on Faulty Clock | 8:30 PM + 4 minutes 30 seconds = 8:34:30 PM |
Clock problems in competitive exams often fall into a few categories:
For clock gaining/losing problems, the key is always to determine the total elapsed time and then calculate the total gain or loss based on the given rate. The final time shown on the faulty clock is the correct time plus the total gain, or the correct time minus the total loss.
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