This problem involves calculating the total number of times a clock buzzes over a specific period, given a pattern based on the hour.
The clock buzzes a number of times equal to the hour it indicates:
We need to find the total buzzes from 12 noon up to and including 11 p.m. Let's list the hours and the corresponding buzzes within this time frame:
To find the total number of buzzes, we need to sum the buzzes for each hour from 12 noon to 11 p.m.
Total Buzzes = Buzzes at 12 noon + Buzzes from 1 PM to 11 PM
Total Buzzes = $12 + (1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 + 11)$
The sum of the first '$n$' natural numbers (1 + 2 + ... + n) can be calculated using the formula:
$ S_n = \frac{n(n+1)}{2} $
In our case, we need the sum of numbers from 1 to 11. So, we set $n = 11$.
Sum (1 to 11) = $S_{11} = \frac{11(11+1)}{2}$
Sum (1 to 11) = $\frac{11 \times 12}{2}$
Sum (1 to 11) = $\frac{132}{2}$
Sum (1 to 11) = $66$
Now, we add the buzzes from 12 noon to this sum:
Total Buzzes = Buzzes at 12 noon + Sum (1 to 11)
Total Buzzes = $12 + 66$
Total Buzzes = $78$
The clock will buzz a total of 78 times from 12 noon till 11 p.m.
What is the value of the missing number?

Consider the following figure :

Find out the missing number from among the following:
Consider the following figure matrix

Study the given pattern carefully and select the number from among the given options that can replace the question mark (?) in it.
| $B_{3}$ | $E_{4}$ | $H_{7}$ |
| $K_{8}$ | $N_{9}$ | ? |
| $T_{11}$ | $W_{13}$ | $Z_{24}$ |