A circle of radius 5 units touches the Co-ordinate axes in the first quadrant. If the circle makes one complete roll on x-axis along the positive direction of x-axis, find its equation in new position.
Let's analyze the problem involving a circle rolling on the x-axis.
Initially, the circle has a radius of 5 units and touches the co-ordinate axes in the first quadrant. When a circle touches both the x and y axes in the first quadrant, its center is located at a point where the distance to the x-axis is equal to the radius and the distance to the y-axis is also equal to the radius. Since the radius is 5 units, the initial center of the circle is at (5, 5).
The equation of the circle in its initial position is given by the standard form: $(x - h)^2 + (y - k)^2 = r^2$, where $(h, k)$ is the center and $r$ is the radius.
Initial equation: $(x - 5)^2 + (y - 5)^2 = 5^2$.
Now, the circle rolls one complete roll on the x-axis along the positive direction. When a circle rolls along a straight line for one complete revolution, the distance covered by its center along that line is equal to the circumference of the circle.
The radius of the circle is $r = 5$ units.
The circumference of the circle is given by the formula $C = 2\pi r$.
Circumference = $2 \times \pi \times 5 = 10\pi$ units.
As the circle rolls one complete turn on the positive x-axis, its center moves a distance equal to its circumference in the positive x direction.
The initial coordinates of the center were $(5, 5)$.
So, the new center of the circle after rolling is $(5 + 10\pi, 5)$.
The radius of the circle remains unchanged during rolling, so the new radius is still $r = 5$ units.
The equation of the circle in its new position, with center $(h', k') = (5 + 10\pi, 5)$ and radius $r' = 5$, is:
$(x - h')^2 + (y - k')^2 = (r')^2$
Substituting the new center coordinates and radius:
$(x - (5 + 10\pi))^2 + (y - 5)^2 = 5^2$
This equation represents the circle's position after one complete roll on the positive x-axis.
Comparing this with the given options, we find that it matches option 3.
| Concept | Explanation | In this Problem |
|---|---|---|
| Initial Center | Circle touching axes in 1st quadrant: (r, r) | Radius = 5, so Center = (5, 5) |
| Rolling Distance | One complete roll covers distance = Circumference (2πr) | Distance = 2π(5) = 10π |
| Movement on X-axis | Center's x-coord increases by rolling distance | New x-coord = 5 + 10π |
| Movement on Y-axis | Center's y-coord remains constant (equal to radius) | New y-coord = 5 |
| New Center | (Initial x + Distance, Initial y) for X-axis roll | (5 + 10π, 5) |
| New Equation | (x - new_h)2 + (y - new_k)2 = r2 | (x - (5 + 10π))2 + (y - 5)2 = 52 |
Understanding how shapes move is key in geometry. When a circle rolls without slipping along a line, the distance covered is directly related to its rotation.
For problems like this, always first identify the initial center and radius. Then, determine the distance and direction of rolling. Finally, calculate the new coordinates of the center and use the standard circle equation form.
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