A carbon compound when heated in excess of concentrated sulphuric acid at 443K gives ethene. The compound is an________.
alcohol
The question describes a chemical reaction where a carbon compound, upon heating with excess concentrated sulfuric acid ($ \text{H}_2\text{SO}_4 $) at 443K, produces ethene ($ \text{C}_2\text{H}_4 $). We need to identify the type of carbon compound that undergoes this transformation.
The reaction described is a classic example of the dehydration of an alcohol. Concentrated sulfuric acid acts as a strong dehydrating agent and catalyst in this process. It removes a molecule of water ($ \text{H}_2\text{O} $) from the alcohol molecule, leading to the formation of an alkene.
The general reaction for the dehydration of an alcohol to an alkene is:
$$ \text{R-CH}_2\text{-CH(OH)-R'} \xrightarrow{\text{Conc. } \text{H}_2\text{SO}_4, 443\text{K}} \text{R-CH=CH-R'} + \text{H}_2\text{O} $$For the specific product to be ethene ($ \text{CH}_2=\text{CH}_2 $), the starting alcohol must be ethanol ($ \text{CH}_3\text{CH}_2\text{OH} $).
The reaction is specifically:
$$ \text{CH}_3\text{CH}_2\text{OH} \xrightarrow{\text{Conc. } \text{H}_2\text{SO}_4, 443\text{K}} \text{CH}_2=\text{CH}_2 + \text{H}_2\text{O} $$Ethanol → Ethene + Water
Let's examine why the other options are incorrect:
Based on the known chemical reactions, alcohols are the class of compounds that readily undergo dehydration in the presence of concentrated sulfuric acid at 443K to form alkenes. Since the product is specified as ethene, the starting compound must be ethanol, which is an alcohol.
Therefore, the carbon compound is an alcohol.
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