A business person buys potatoes of two different varieties P and Q, mixes them in a certain ratio and sells them at ₹192 per kg.
The cost of the variety P is ₹800 for 5 kg.
The cost of the variety Q is ₹800 for 4 kg.
If the person gets 8% profit, what is the P : Q ratio (by weight)?
This problem requires finding the ratio of two potato varieties, P and Q, by weight, given their costs, a selling price, and a profit percentage. We will use the concept of cost price, selling price, profit, and the rule of alligation.
First, determine the cost price per kilogram for each variety:
The business person sells the mixture at ₹192 per kg and makes an 8% profit. The mean cost price of the mixture can be calculated using the formula: $CP = \frac{SP}{1 + \text{Profit%}}$.
We now use the rule of alligation with the cost prices of variety P, variety Q, and the mean cost price of the mixture.
Apply alligation:
The ratio of P to Q is given by the inverse ratio of these differences:
Therefore, the ratio P : Q (by weight) is 5:4.
One cup has juice and water in the ratio 5 ∶ 2, while another cup of the same capacity has them in the ratio 7 ∶ 4, respectively. If contents of both the cups (when full) are poured in a vessel, then what will be the final ratio of water to juice in the vessel?
A and B are solutions of acid and water. The ratios of water and acid in A and B are 4 : 5 and 1 : 2 respectively. If x liters of A is mixed with y liters of B, then the ratio of water and acid in the mixture becomes 8 : 13 What is x : y?
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