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Question

A business person buys potatoes of two different varieties P and Q, mixes them in a certain ratio and sells them at ₹192 per kg. 
The cost of the variety P is ₹800 for 5 kg. 
The cost of the variety Q is ₹800 for 4 kg. 
If the person gets 8% profit, what is the P : Q ratio (by weight)?

The correct answer is
5:4

Potato Mix Ratio Calculation

This problem requires finding the ratio of two potato varieties, P and Q, by weight, given their costs, a selling price, and a profit percentage. We will use the concept of cost price, selling price, profit, and the rule of alligation.

Calculate Cost Price per kg for Varieties P and Q

First, determine the cost price per kilogram for each variety:

  • Variety P: ₹800 for 5 kg. Cost per kg = $\frac{800}{5} = ₹160$ per kg.
  • Variety Q: ₹800 for 4 kg. Cost per kg = $\frac{800}{4} = ₹200$ per kg.

Determine the Mean Cost Price (CP)

The business person sells the mixture at ₹192 per kg and makes an 8% profit. The mean cost price of the mixture can be calculated using the formula: $CP = \frac{SP}{1 + \text{Profit%}}$.

  • Selling Price (SP) = ₹192 per kg
  • Profit = 8% = 0.08
  • Mean CP = $\frac{192}{1 + 0.08} = \frac{192}{1.08}$
  • Calculation: $\frac{192}{1.08} = \frac{19200}{108}$. Simplifying this fraction gives $\frac{1600}{9}$.
  • So, the Mean CP of the mixture is $₹\frac{1600}{9}$ per kg.

Apply Alligation Rule to Find P : Q Ratio

We now use the rule of alligation with the cost prices of variety P, variety Q, and the mean cost price of the mixture.

  • Cost Price of P ($CP_P$): ₹160 per kg
  • Cost Price of Q ($CP_Q$): ₹200 per kg
  • Mean Cost Price (Mean CP): $₹\frac{1600}{9}$ per kg

Apply alligation:

  • Difference between $CP_Q$ and Mean CP: $200 - \frac{1600}{9} = \frac{1800 - 1600}{9} = \frac{200}{9}$
  • Difference between Mean CP and $CP_P$: $\frac{1600}{9} - 160 = \frac{1600 - 1440}{9} = \frac{160}{9}$

The ratio of P to Q is given by the inverse ratio of these differences:

  • Ratio P : Q = (Difference Q : Mean CP) : (Mean CP : Difference P)
  • Ratio P : Q = $\frac{200}{9} : \frac{160}{9}$
  • Simplifying the ratio: $200 : 160 = 20 : 16 = 5 : 4$.

Therefore, the ratio P : Q (by weight) is 5:4.

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Important Questions from To Make a Mixture from Two Mixtures

  1. In a 90 litre solution, acid and water are in the ratio 2 ∶ 1, To make the ratio of acid and water as 1 ∶ 2, how many litre of water should be added to the solution?

  2. In a milk and water solution, the ratio of milk to water is 1 : 4. M litres of milk is added in it and ratio become 1 : 3. Again N litres of water is added in it and ratio become 2 : 7. If N – M = 4, then what is the initial quantity of solution?

  3. A mixture contains acid and alcohol in the ratio of 3 : 2. On adding 10 litres of alcohol in mixture, the ratio of acid to alcohol becomes 3 : 5. The quantity of acid (in litres) in the original mixture was:

  4. How many litres of acid are there in 12 litres of a 20% solution?

  5. A mixture of fog contains water and air in the ratio 5 ∶ 3. On adding 8 liters of air, the ratio of water and air becomes 1 ∶ 1. The quantity of water in the original fog is: 

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