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Question

A bought an article at a certain price and sold it at 10% profit. B bought the same article at a price 10% lesser than A and sold it at ₹18 lesser than A. B's gain percentage in this deal is 20%. At what price B bought the article?

The correct answer is
₹810

Solving for B's Purchase Price

This problem involves comparing the buying and selling prices of an article between two people, A and B, considering profit percentages and price differences. We need to determine the price at which B bought the article.

Understanding the Transactions

  • A's Transaction: A buys an article at a certain price and sells it making a 10% profit.
  • B's Transaction: B buys the same article at a price 10% less than A's purchase price. B then sells it ₹18 less than A's selling price, achieving a 20% gain.

Step-by-Step Calculation

Let's use variables to represent the unknown prices:

  • Let $P_A$ be the price A paid for the article (A's Cost Price).

Calculating A's Selling Price ($SP_A$)

A sold the article at a 10% profit. The selling price is calculated as:

$SP_A = P_A + (10\% \text{ of } P_A)$
$SP_A = P_A + \frac{10}{100} \times P_A$
$SP_A = P_A + 0.10 P_A$
$SP_A = 1.10 P_A$

Calculating B's Cost Price ($CP_B$)

B bought the article at a price 10% lesser than A's purchase price ($P_A$).

$CP_B = P_A - (10\% \text{ of } P_A)$
$CP_B = P_A - \frac{10}{100} \times P_A$
$CP_B = P_A - 0.10 P_A$
$CP_B = 0.90 P_A$

Calculating B's Selling Price ($SP_B$)

B sold the article at ₹18 lesser than A's selling price ($SP_A$).

$SP_B = SP_A - 18$
Substituting the expression for $SP_A$:
$SP_B = (1.10 P_A) - 18$

Using B's Profit Percentage

B made a 20% gain on his purchase price ($CP_B$). This means:

$SP_B = CP_B + (20\% \text{ of } CP_B)$
$SP_B = CP_B + \frac{20}{100} \times CP_B$
$SP_B = CP_B + 0.20 CP_B$
$SP_B = 1.20 CP_B$

Setting up the Equation to Solve for $P_A$

Now we equate the two expressions for $SP_B$ and substitute the expression for $CP_B$ in terms of $P_A$:

$1.10 P_A - 18 = 1.20 \times (0.90 P_A)$
$1.10 P_A - 18 = 1.08 P_A$

Now, we solve this equation for $P_A$:

$1.10 P_A - 1.08 P_A = 18$
$0.02 P_A = 18$
$P_A = \frac{18}{0.02}$
$P_A = \frac{1800}{2}$
$P_A = 900$

So, A's purchase price was ₹900.

Finding B's Purchase Price

The question asks for the price at which B bought the article ($CP_B$). We calculated this earlier:

$CP_B = 0.90 P_A$
$CP_B = 0.90 \times 900$
$CP_B = 810$

Therefore, B bought the article at ₹810.

Final Answer Check

If $P_A = 900$:

  • $SP_A = 1.10 \times 900 = 990$.
  • $CP_B = 0.90 \times 900 = 810$.
  • $SP_B = SP_A - 18 = 990 - 18 = 972$.
  • B's profit = $SP_B - CP_B = 972 - 810 = 162$.
  • B's profit percentage = $\frac{\text{Profit}}{CP_B} \times 100 = \frac{162}{810} \times 100 = \frac{1}{5} \times 100 = 20\%$.

This matches the information given in the problem.

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Important Questions from Profit & Loss (Notes)

  1. A person incurs a loss of 10% by selling a watch for Rs. 450. At what price should the watch be sold to earn 10% profit?
  2. Two bikes were sold for a total of ₹ $1,50,000$. One bike was sold at $33\frac{1}{3}\%$ loss and the other at $20\%$ profit. The cost price of the first bike is equal to the selling price of the other bike. Find the over all loss.

  3. What will be the profit percentage on selling an article at a certain price if there is $30\%$ loss on selling the article at $\frac{3}{5}$ of the selling price?

  4. A shopkeeper bought an item for ₹7825 and marked it at 30% higher than the cost price. If he sells the item by allowing 20% discount, then his profit percentage will be :
  5. 100 पुस्तकों का क्रय मूल्य 60 पुस्तकों के विक्रय मूल्य के बराबर है । लाभ प्रतिशत _______________ होगा ।

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