This problem involves comparing the buying and selling prices of an article between two people, A and B, considering profit percentages and price differences. We need to determine the price at which B bought the article.
Let's use variables to represent the unknown prices:
A sold the article at a 10% profit. The selling price is calculated as:
$SP_A = P_A + (10\% \text{ of } P_A)$
$SP_A = P_A + \frac{10}{100} \times P_A$
$SP_A = P_A + 0.10 P_A$
$SP_A = 1.10 P_A$
B bought the article at a price 10% lesser than A's purchase price ($P_A$).
$CP_B = P_A - (10\% \text{ of } P_A)$
$CP_B = P_A - \frac{10}{100} \times P_A$
$CP_B = P_A - 0.10 P_A$
$CP_B = 0.90 P_A$
B sold the article at ₹18 lesser than A's selling price ($SP_A$).
$SP_B = SP_A - 18$
Substituting the expression for $SP_A$:
$SP_B = (1.10 P_A) - 18$
B made a 20% gain on his purchase price ($CP_B$). This means:
$SP_B = CP_B + (20\% \text{ of } CP_B)$
$SP_B = CP_B + \frac{20}{100} \times CP_B$
$SP_B = CP_B + 0.20 CP_B$
$SP_B = 1.20 CP_B$
Now we equate the two expressions for $SP_B$ and substitute the expression for $CP_B$ in terms of $P_A$:
$1.10 P_A - 18 = 1.20 \times (0.90 P_A)$
$1.10 P_A - 18 = 1.08 P_A$
Now, we solve this equation for $P_A$:
$1.10 P_A - 1.08 P_A = 18$
$0.02 P_A = 18$
$P_A = \frac{18}{0.02}$
$P_A = \frac{1800}{2}$
$P_A = 900$
So, A's purchase price was ₹900.
The question asks for the price at which B bought the article ($CP_B$). We calculated this earlier:
$CP_B = 0.90 P_A$
$CP_B = 0.90 \times 900$
$CP_B = 810$
Therefore, B bought the article at ₹810.
If $P_A = 900$:
This matches the information given in the problem.