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Question

A body covers a straight-line distance of 10 m from point A to B in 5 s and then covers back the distance from point B to point A along the same straight path in 5 s. How much will be the average speed of the body?

The correct answer is
2 m/s

Calculating Average Speed: Motion A to B and Back

The question asks for the average speed of a body that travels from point A to point B and then returns to point A along the same straight path.

  • Distinguish Speed vs. Velocity: Average speed depends on the total distance covered, while average velocity depends on the net displacement.

Step-by-Step Calculation

  1. Calculate Total Distance:

    • Distance from A to B = 10 m
    • Distance from B to A = 10 m
    • Total Distance = Distance (A to B) + Distance (B to A) = 10 m + 10 m = 20 m
  2. Calculate Total Time:

    • Time taken from A to B = 5 s
    • Time taken from B to A = 5 s
    • Total Time = Time (A to B) + Time (B to A) = 5 s + 5 s = 10 s
  3. Calculate Average Speed:

    • The formula for average speed is:
      $ \text{Average Speed} = \frac{\text{Total Distance}}{\text{Total Time}} $
    • Substitute the calculated values:
      $ \text{Average Speed} = \frac{20 \text{ m}}{10 \text{ s}} $
    • $ \text{Average Speed} = 2 \text{ m/s} $

Therefore, the average speed of the body is 2 m/s.

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Important Questions from Speed and Velocity

  1. The given equation provides the property of the motion of an object, traversing a circular path. What is ‘v’ in this equation?

    ac = v2/R

  2. The basic unit of speed of an object is ______.

  3. Which of the following quantities specifies its speed with direction?

  4. Which of the following represents non-uniform linear velocity?
  5. Which of the following describes the nature of the average speed?
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