A, B, C, D, E and F live on six different floors of the same building. The lowermost floor in the building is numbered 1, the floor above it, number 2 and so on, till the topmost floor is numbered 6. B lives on a floor that is a prime number. The product of floors on which B and D live is 3. Only 2 people live above C. F lives immediately below A. How many people live between A and C?
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This puzzle requires careful deduction based on the given clues about six people (A, B, C, D, E, F) living on six floors of a building, numbered 1 to 6 from bottom to top.
B_{floor} \times D_{floor} = 3. Since floors are integers, the only possible pairs of floors for (B, D) are (1, 3) or (3, 1).Let's check the possible pairs for (F, A) against the floors already occupied:
Now, let's examine the possible (F, A) pairs:
Therefore, F lives on floor 5 and A lives on floor 6.
The final arrangement of people on the floors is:
| Floor 6: A |
| Floor 5: F |
| Floor 4: C |
| Floor 3: B |
| Floor 2: E (The only remaining person and floor) |
| Floor 1: D |
The question asks: How many people live between A and C?
Therefore, there is 1 person (F) living between A and C.
If T joined P, Q, R and S, and T was on the third step, and Q was on a higher step than T, which step must be vacant?
If there are two steps in between the steps on which A and D are standing and C is standing on Step 6, A must be standing on which of the following steps?