A 7 m 20 cm pole casts a shadow of length 8 m 30 cm. Find the height of a tree that casts a shadow of length 6 m 64 cm, under similar conditions.
5 m 76 cm
This problem involves similar triangles formed by the pole and its shadow, and the tree and its shadow. When the sun is in the same position (similar conditions), the ratio of the height of an object to the length of its shadow is constant.
It's easiest to work with a single unit, like centimeters. Let's convert all given lengths:
Under similar conditions, the ratio of height to shadow length is the same for the pole and the tree. Let 'h' be the height of the tree in centimeters.
Ratio for pole = $\frac{\text{Pole height}}{\text{Pole shadow length}} = \frac{\text{720 cm}}{\text{830 cm}}$
Ratio for tree = $\frac{\text{Tree height}}{\text{Tree shadow length}} = \frac{\text{h cm}}{\text{664 cm}}$
Since the conditions are similar, we can set these ratios equal to each other:
$\frac{h}{\text{664}} = \frac{\text{720}}{\text{830}}$
Now, we solve the proportion for 'h':
$h = \frac{\text{720}}{\text{830}} \times \text{664}$
$h = \frac{\text{72}}{\text{83}} \times \text{664}$
To calculate this value:
$h = \frac{\text{47808}}{\text{83}}$
Performing the division:
$h \approx \text{576 cm}$
The height of the tree is approximately 576 cm. Let's convert this back to meters and centimeters:
$\text{576 cm} = \text{500 cm} + \text{76 cm} = \text{5 m} + \text{76 cm}$
So, the height of the tree is approximately 5 m 76 cm.
This calculated height matches one of the given options.
Mohit is standing at some distance from a 60 meters tall building. Mohit is 1.8 meters tall. When Mohit walks towards the building, then the angle of elevation from his head becomes 60° from 45°. How much distance (in metres) Mohit covered towards the building?
A peacock sitting at the top of a 3 meter high pole saw a snake approaching towards pole at a distance three times of the height of the pole. Then it jumping from pole will catch the snake at what distance from the pole if both are running with same speed ?
The foot of a ladder 25 m long is 7 m from the base of the building. If the top of the ladder slips by 4 m, then by how much distance will the foot of the ladder slide?
Two hotels stand 25 m apart. One of them is 70 m high and the angle of depression of the top of other as observed from the top of this hotel is 45°. Height of the other hotel is:
The angle of depression of the foot of a building from the top of a tower 50 m away is 60°. How high is the tower?