The total volume of the mixture is 460 litres.
The initial ratio of milk to water is 11:12.
Calculate the total parts in the ratio: $11 + 12 = 23$ parts.
Determine the volume represented by one part: $\frac{460 \text{ litres}}{23 \text{ parts}} = 20 \text{ litres/part}$.
Calculate the initial quantity of milk: $11 \text{ parts} \times 20 \text{ litres/part} = 220 \text{ litres}$.
Calculate the initial quantity of water: $12 \text{ parts} \times 20 \text{ litres/part} = 240 \text{ litres}$.
Let the amount of milk to be added be $x$ litres.
After adding milk, the new quantity of milk will be $220 + x$ litres.
The quantity of water remains unchanged at $240$ litres.
The required new ratio of milk to water is 3:2.
Set up the equation based on the new ratio:
$ \frac{\text{New Milk Quantity}}{\text{Water Quantity}} = \frac{3}{2} $
$ \frac{220 + x}{240} = \frac{3}{2} $
To solve for $x$, cross-multiply:
$ 2 \times (220 + x) = 3 \times 240 $
$ 440 + 2x = 720 $
Subtract 440 from both sides:
$ 2x = 720 - 440 $
$ 2x = 280 $
Divide by 2 to find $x$:
$ x = \frac{280}{2} $
$ x = 140 $
Thus, 140 litres of milk must be added.
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