The initial solution has a volume of 360 ml and contains 40% alcohol.
The amount of pure alcohol in the initial solution is:
Amount of Alcohol = 40% of 360 ml
$ \text{Amount of Alcohol} = 0.40 \times 360 \, \text{ml} = 144 \, \text{ml} $
Water is added to the solution. The volume of added water is 3600 ml.
The new total volume is the initial volume plus the added water:
$ \text{New Volume} = 360 \, \text{ml} + 3600 \, \text{ml} = 3960 \, \text{ml} $
The amount of alcohol remains the same (144 ml), but the total volume has increased.
The new percentage of alcohol is calculated as:
$ \text{New Percentage} = \left( \frac{\text{Amount of Alcohol}}{\text{New Volume}} \right) \times 100\% $
$ \text{New Percentage} = \left( \frac{144 \, \text{ml}}{3960 \, \text{ml}} \right) \times 100\% $
$ \text{New Percentage} \approx 0.03636 \times 100\% \approx 3.636\% $
The approximate percentage of alcohol in the new solution is 3.6%.
Suppose a tap mixes hot water and cold water in a ratio that depends linearly on the proportion of opening. Water out of the tap has temperature 40°C when the tap is half-open, and 30°C when it is three-fourths open. To get water at 50°C, the tap should be_______________.