A 253 m long train running at a speed of 60 km/h takes 42 seconds to cross a bridge. The length (in m) of the bridge is:
447
This problem involves a train of a certain length crossing a bridge. When a train crosses a bridge, the total distance it covers is equal to the length of the train plus the length of the bridge. The train starts to cross the bridge when its front end reaches the beginning of the bridge and finishes crossing when its rear end leaves the end of the bridge.
We are given the following information:
We need to find the length of the bridge, $L_{\text{bridge}}$, in meters.
The speed is given in kilometers per hour (km/h), but the time is in seconds and the lengths are in meters. We need to convert the speed from km/h to meters per second (m/s) to maintain consistent units for calculation. The conversion factor from km/h to m/s is $\frac{5}{18}$.
Speed in m/s $= 60 \times \frac{5}{18}$ m/s
Speed in m/s $= \frac{10 \times 5}{3}$ m/s
Speed in m/s $= \frac{50}{3}$ m/s
The total distance covered by the train while crossing the bridge is calculated using the formula:
$\text{Distance} = \text{Speed} \times \text{Time}$
Total distance $D = S \times T$
$D = \frac{50}{3} \text{ m/s} \times 42 \text{ s}$
$D = 50 \times \frac{42}{3}$ m
$D = 50 \times 14$ m
$D = 700$ m
This total distance of 700 m is the combined length of the train and the bridge.
As explained earlier, the total distance covered by the train to cross the bridge is the sum of its own length and the length of the bridge.
Total distance $D = L_{\text{train}} + L_{\text{bridge}}$
We know $D = 700$ m and $L_{\text{train}} = 253$ m. We can rearrange the formula to find $L_{\text{bridge}}$:
$L_{\text{bridge}} = D - L_{\text{train}}$
$L_{\text{bridge}} = 700 \text{ m} - 253 \text{ m}$
$L_{\text{bridge}} = 447 \text{ m}$
Thus, the length of the bridge is 447 meters.
| Quantity | Value |
|---|---|
| Train Length ($L_{\text{train}}$) | 253 m |
| Train Speed (S) | 60 km/h ($ = \frac{50}{3}$ m/s) |
| Time Taken (T) | 42 s |
| Total Distance (D) | 700 m |
| Bridge Length ($L_{\text{bridge}}$) | 447 m |
| Concept | Explanation | Formula |
|---|---|---|
| Distance Covered | When a train crosses a bridge (or any object with length), the distance is the sum of train length and object length. | $D = L_{\text{train}} + L_{\text{object}}$ |
| Speed-Distance-Time Relation | Relates speed, distance, and time for uniform motion. | $D = S \times T$ |
| Unit Conversion (km/h to m/s) | Converting speed units is essential for consistency in calculations. | Multiply by $\frac{5}{18}$ |
Train problems are common in aptitude tests and physics. They often involve relative speed and the concept of distance covered based on the train's length and the length of the object being crossed.
Always ensure that all units (speed, time, distance) are consistent before performing calculations.
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