A 20 mm diameter through-hole is to be drilled in a 30 mm thick plate using a double fluted, 120° lip angle drill. The drill tip is at a distance of 3 mm from the plate surface when cutting started and an over travel of 2 mm is recommended. If the drill rotates at 500 rev/min and the feed per revolution is 0.1 mm, the machining time of operation (in sec) will be
This problem asks us to determine the time it takes to drill a through-hole in a metal plate, considering various factors like plate thickness, drill geometry, initial position, overtravel, rotational speed, and feed rate.
To calculate the machining time for drilling, we need to find the total distance the drill must travel along its axis (the total depth of cut) and the rate at which it travels (the feed rate).
The total distance the drill tip travels includes several components:
The length of the drill tip ($L_{tip}$) can be calculated using the drill diameter (D) and the drill's lip angle ($2\alpha$). The formula relates the tip length to the radius (D/2) and the cotangent of the semi-lip angle ($\alpha$).
Given:
First, find the semi-lip angle:
\(\alpha = \frac{120^{\circ}}{2} = 60^{\circ}\)
Now, calculate the drill tip length:
\(L_{tip} = \frac{D}{2} \times \cot(\alpha)\)
\(L_{tip} = \frac{20 \text{ mm}}{2} \times \cot(60^{\circ})\)
\(L_{tip} = 10 \text{ mm} \times \frac{1}{\sqrt{3}}\)
\(L_{tip} \approx 10 \text{ mm} \times 0.57735\)
\(L_{tip} \approx 5.7735 \text{ mm}\)
Now we sum up all the components of the total depth of cut:
Total Depth of Cut, \(L_{total} = \text{Plate Thickness} + \text{Initial Gap} + \text{Overtravel} + L_{tip}\)
\(L_{total} = 30 \text{ mm} + 3 \text{ mm} + 2 \text{ mm} + 5.7735 \text{ mm}\)
\(L_{total} = 40.7735 \text{ mm}\)
The feed rate ($V_f$) is the speed at which the drill moves axially into the material. It is calculated by multiplying the feed per revolution by the rotational speed.
Given:
Feed Rate, \(V_f = f \times N\)
\(V_f = 0.1 \text{ mm/rev} \times 500 \text{ rev/min}\)
\(V_f = 50 \text{ mm/min}\)
The machining time ($T_m$) is the total distance traveled divided by the feed rate.
\(T_m = \frac{L_{total}}{V_f}\)
\(T_m = \frac{40.7735 \text{ mm}}{50 \text{ mm/min}}\)
\(T_m \approx 0.81547 \text{ minutes}\)
The question asks for the time in seconds. To convert minutes to seconds, multiply by 60.
\(T_m (\text{in seconds}) = T_m (\text{in minutes}) \times 60\)
\(T_m (\text{in seconds}) \approx 0.81547 \times 60\)
\(T_m (\text{in seconds}) \approx 48.9282 \text{ seconds}\)
Rounding to two decimal places, the machining time is approximately 48.93 seconds, which is very close to 48.92 seconds.
| Parameter | Value | Unit |
|---|---|---|
| Drill Diameter (D) | 20 | mm |
| Plate Thickness | 30 | mm |
| Initial Gap | 3 | mm |
| Overtravel | 2 | mm |
| Lip Angle (\(2\alpha\)) | 120 | ° |
| Semi-lip Angle (\(\alpha\)) | 60 | ° |
| Rotational Speed (N) | 500 | rev/min |
| Feed per Revolution (f) | 0.1 | mm/rev |
| Drill Tip Length (\(L_{tip}\)) | 5.7735 | mm |
| Total Depth of Cut (\(L_{total}\)) | 40.7735 | mm |
| Feed Rate (\(V_f\)) | 50 | mm/min |
| Machining Time (in minutes) | 0.81547 | minutes |
| Machining Time (in seconds) | 48.9282 | seconds |
The calculated machining time is approximately 48.93 seconds.
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