A 10 Pole AC generator rotates at 1200 rpm. What will be the frequency of generated AC?
100 Hz
The frequency of the alternating current (AC) generated by an AC generator depends on two main factors: the number of poles in the generator and the speed at which the rotor rotates.
In this question, we are given:
We need to find the frequency of the generated AC.
The relationship between the frequency (f), the number of poles (P), and the speed of rotation (N) is given by the formula:
\(f = \frac{P \times N}{120}\)
Where:
Let's plug in the given values into the formula:
\(f = \frac{10 \times 1200}{120}\)
First, multiply the number of poles by the speed:
\(10 \times 1200 = 12000\)
Now, divide this result by 120:
\(f = \frac{12000}{120}\)
\(f = 100\)
So, the frequency of the generated AC is 100 Hz.
A generator with 10 poles rotating at 1200 rpm will produce an AC voltage that completes 100 cycles every second. This is the frequency of the generated AC power.
Let's look at the options provided:
Our calculated frequency of 100 Hz matches one of the options.
Which of the following is NOT true of parallel operation of alternators?
What happens to the terminal voltage when an alternator is connected to an infinite bus bar and its excitation is gradually increased?
Consider two alternators running in parallel. Now if the excitation of the one of the alternators is changed, then:
The frequency of 6 pole alternators running at 1500 RPM is:
The rating of an alternator is expressed in