Question
A 10 ½ digit timer counter possesses a base clock of frequency 100 MHz. When measuring a particular input, the reading obtained is the same in: (i) Frequency mode of operation with a gating time of one second and (ii) Period mode of operation (in the × 10 ns scale). The frequency of the unknown input (reading obtained) in Hz is _____________.
For frequency mode of operation
\(f = \frac{n}{t}\)
f is frequency of input signal
n is number of cycles
t is gating time
n = 100 × 106
t = 1 sec
f = 108 cycles/sec
In period made period P of input signal is the inverse of its frequency
\(P = \frac{1}{f} = \frac{1}{{{{10}^8}}} = 10\;ns\)
On 10 ½ digit display,
Frequency is displayed as 10000000.00 Hz
Period is displayed as 10.00000000 nsWas this answer helpful?
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