40 men can complete a work in 15 days. Three days after they started working, 20 more men joined them. In how many days the total work will be completed?
11
This problem involves the concept of work and time, specifically how the number of workers affects the time taken to complete a task. The core idea is that the total amount of work remains constant, regardless of the number of workers or the time taken, assuming the work rate per person is constant.
The total work required to complete the task can be calculated by multiplying the number of men initially assigned by the number of days they would take alone.
Initial number of men = 40
Days to complete work by 40 men = 15 days
Total Work = Number of men $\times$ Number of days
Total Work = $40 \times 15 = 600$ units of work
So, the total work is 600 units.
The 40 men worked for the first 3 days before more men joined. We need to calculate how much work was completed during this initial period.
Number of men in the first 3 days = 40
Days worked initially = 3 days
Work done in first 3 days = Number of men $\times$ Number of days worked
Work done in first 3 days = $40 \times 3 = 120$ units of work
After 3 days, 120 units of work have been completed.
Subtract the work done in the first 3 days from the total work to find the work that still needs to be completed.
Remaining Work = Total Work - Work done in first 3 days
Remaining Work = $600 - 120 = 480$ units of work
There are 480 units of work remaining.
After 3 days, 20 more men joined the initial group of 40 men.
Initial men = 40
Men joined = 20
New number of men = Initial men + Men joined
New number of men = $40 + 20 = 60$ men
The remaining work will be done by 60 men.
Now, the 480 units of remaining work will be completed by the new team of 60 men. Assuming each man works at the same rate, the time taken will be the remaining work divided by the new number of men.
Days to complete remaining work = Remaining Work / New number of men
Days to complete remaining work = $480 / 60 = 8$ days
The remaining work will take 8 more days to complete.
The total time taken to complete the entire work is the sum of the days worked initially and the days taken to complete the remaining work.
Total Days = Days worked initially + Days to complete remaining work
Total Days = $3 \text{ days} + 8 \text{ days} = 11 \text{ days}
The total work will be completed in 11 days.
| Step | Description | Calculation | Result |
|---|---|---|---|
| 1 | Total Work | $40 \times 15$ | 600 units |
| 2 | Work Done in 3 Days | $40 \times 3$ | 120 units |
| 3 | Remaining Work | $600 - 120$ | 480 units |
| 4 | New Number of Men | $40 + 20$ | 60 men |
| 5 | Days for Remaining Work | $480 / 60$ | 8 days |
| 6 | Total Days | $3 + 8$ | 11 days |
Therefore, the total work will be completed in 11 days.
| Concept | Formula/Relationship | Explanation |
|---|---|---|
| Total Work | Work = Men $\times$ Days | Assuming a constant work rate per man, total work is proportional to the number of men and the time they work. |
| Work Rate | Work Rate per Man = Total Work / (Men $\times$ Days) | The amount of work one man can do in one day. Often assumed constant in these problems. |
| Effect of More Men | If Men increase, Days decrease (for the same work) | If the number of men increases, they can complete the same amount of work in less time, assuming the same work rate. |
| Partial Work | Work Done = Men $\times$ Days Worked | Calculates the portion of total work completed in a specific period by a specific number of men. |
Problems involving work and time often relate to direct and inverse proportion:
In this problem, when more men join, the remaining work is completed faster due to the inverse relationship between the number of men and the days required for a fixed amount of work.
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