All Exams Test series for 1 year @ ₹349 only
Question

25 persons are in a room. 15 of them play hockey, 17 of them play football and 10 of them play both hockey and football. Then the number of persons playing neither hockey nor football is:

The correct answer is

3

This question involves applying basic principles of set theory to determine the number of individuals who do not participate in either of two given activities. We are provided with the total number of persons in a room, the number of persons playing hockey, the number of persons playing football, and the number of persons playing both sports. Our goal is to find the number of persons playing neither hockey nor football.

Persons in the Room: Understanding the Data

Let's first list down the information provided in the question related to the persons playing sports:

  • Total number of persons in the room = 25
  • Number of persons who play hockey = 15
  • Number of persons who play football = 17
  • Number of persons who play both hockey and football = 10

Key Concepts for Persons Playing Sports

To solve this problem, we will use the principles of set theory. Let H be the set of persons who play hockey and F be the set of persons who play football. The total number of persons is represented by the universal set U.

The formula for the union of two sets, which represents the number of persons playing at least one of the two sports (hockey or football), is given by:

\(N(H \cup F) = N(H) + N(F) - N(H \cap F)\)

Where:

  • \(N(H)\) is the number of persons playing hockey.
  • \(N(F)\) is the number of persons playing football.
  • \(N(H \cap F)\) is the number of persons playing both hockey and football (the intersection).
  • \(N(H \cup F)\) is the number of persons playing at least one of the sports (the union).

Once we find the number of persons playing at least one sport, we can determine the number of persons playing neither sport by subtracting this value from the total number of persons in the room.

\(N(\text{neither H nor F}) = N(U) - N(H \cup F)\)

Calculating Persons Playing Neither Sport

Let's perform the calculations step-by-step using the given data about the persons.

Step 1: Calculate the number of persons playing at least one sport (Hockey or Football)

Using the formula for the union of sets:

\(N(H \cup F) = N(H) + N(F) - N(H \cap F)\)

Substitute the given values into the formula:

\(N(H \cup F) = 15 + 17 - 10\)

\(N(H \cup F) = 32 - 10\)

\(N(H \cup F) = 22\)

So, 22 persons play at least one of the two sports (hockey or football).

Step 2: Calculate the number of persons playing neither hockey nor football

The total number of persons in the room is 25. To find the number of persons who play neither sport, we subtract the number of persons playing at least one sport from the total number of persons:

\(N(\text{neither H nor F}) = N(U) - N(H \cup F)\)

\(N(\text{neither H nor F}) = 25 - 22\)

\(N(\text{neither H nor F}) = 3\)

Therefore, 3 persons play neither hockey nor football.

Summary of Persons Playing Statistics

Here is a summary of the data and the calculated result, helping to visualize the breakdown of persons:

Category Number of Persons
Total Persons in the Room 25
Persons Playing Hockey Only \(15 - 10 = 5\)
Persons Playing Football Only \(17 - 10 = 7\)
Persons Playing Both Hockey and Football 10
Persons Playing At Least One Sport 22
Persons Playing Neither Hockey Nor Football 3

The number of persons playing neither hockey nor football is 3.

Was this answer helpful?

Important Questions from Numerical Estimation

  1. 1200 men and 500 women can build a bridge in 2 weeks. 900 men and 250 women will take 3 weeks to build the same bridge. How many men will be needed to build the bridge in one week?

  2. The number of 3-digit numbers such that the digit 1 is never to the immediate right of 2 is

  3. Students applying for hostel rooms are allotted rooms in order of seniority. Students already staying in a room will move if they get a room in their preferred list. Preferences of lower ranked applicants are ignored during allocation.

    Given the data below, which room will Ajit stay in?

    Names

    Student seniority

    Current

    Room preference list

    Amar

    1

    P

    R, S, Q

    Akbar

    2

    None

    R, S

    Anthony

    3

    Q

    P

    Ajit

    4

    S

    Q, P, R

  4. There are 16 teachers who can teach Thermodynamics (TD), 11 who can teach Electrical Sciences (ES), and 5 who can teach both TD and Engineering Mechanics (EM). There are a total of 40 teachers. 6 cannot teach any of the three subjects, i.e. EM, ES or TD. 6 can teach only ES. 4 can teach all three subjects, i.e. EM, ES and TD. 4 can teach ES and TD. How many can teach both ES and EM but not TD?

  5. If |4X – 7| = 5 then the values of 2 |X| - | - X| is:

Need Expert Advice?

Start Your Preparation with Prepp Mobile App

Download the app from Google Play & App Store
Download the app from Google Play & App Store
Prepp Mobile App