1 atmospheric pressure =
1.01 × 10 5 Pa
Atmospheric pressure is the pressure exerted by the weight of the air column above a given point on Earth's surface. It changes with altitude, weather conditions, and temperature. However, there is a standard value defined for atmospheric pressure at sea level under standard conditions.
The standard atmospheric pressure (atm) is a unit of pressure. It is defined as the average pressure at sea level at a temperature of 15°C. While 'atm' is a unit itself, it is often converted into SI units like Pascals (Pa) or bars.
The internationally accepted value for 1 standard atmospheric pressure in Pascals is approximately $101,325$ Pa. This can also be expressed in scientific notation.
$101,325$ Pa $= 1.01325 \times 10^5$ Pa.
For many calculations and educational purposes, this value is often rounded to $1.01 \times 10^5$ Pa.
Let's look at the given options and compare them to the standard value of 1 atmospheric pressure in Pascals:
Comparing the standard value ($1.01325 \times 10^5$ Pa, often rounded to $1.01 \times 10^5$ Pa) with the options, we find that Option 3 matches the rounded standard value for 1 atmospheric pressure in Pascals.
Therefore, 1 atmospheric pressure is equal to approximately $1.01 \times 10^5$ Pa.
| Unit | Symbol | Equivalent in Pascals (approx.) |
|---|---|---|
| Pascal | Pa | 1 Pa |
| Atmosphere | atm | $1.01 \times 10^5$ Pa |
| Bar | bar | $1 \times 10^5$ Pa |
| Millimeters of Mercury | mmHg / torr | 133.32 Pa |
| Pounds per Square Inch | psi | 6894.76 Pa |
Atmospheric pressure is a fundamental concept in physics and meteorology. Here are a few points to remember:
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