UGC NET 2018 Paper 2 Electronic Science Question Paper (19-Dec-2018) (Shift 1); Download PDF

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UGC NET 2018 Paper 2 Electronic Science Question Paper (19-Dec-2018) (Shift 1); Download PDF

UGC NET 2018 Paper 2 Electronic Science (Shift 1), held on 19 December 2018, was a crucial examination for candidates aspiring to qualify for Assistant Professor and Junior Research Fellowship (JRF) in Electronic Science. The exam followed a structured pattern with 100 multiple-choice questions (MCQs), each worth 2 marks, to be completed in 2 hours without negative marking. Solving this question paper will help candidates gauge the exam's difficulty level, identify important topics, and refine their time management strategies for better performance in future attempts.

Free

UGC NET 2018 Paper 2 Electronic Science Prev Year Paper (19-Dec-2018) (Shift 1)

120 Minutes

100 Questions

200 Marks

English

Showing 1 - 5 of 100 questions

Page 1 of 20

Q1.

A transistor with β = 100 is to be used in the emitter feedback bias configuration. If R _e= 2 kΩ, R _b= 370 kΩ the stability factor is

1.57

32.5

Q2.

An exact position of Fermi level in an n-type semiconductor is

\({E_C} - KT\ln \left[ {\frac{{{N_C}}}{{{N_D}}}} \right]\)

\({E_C} + KT\ln \left[ {\frac{{{N_C}}}{{{N_D}}}} \right]\)

\({E_C} - KT\ln \left[ {\frac{{{N_CN_V}}}{{{N_D}}}} \right]\)

\({E_C} - KT\ln \left[ {\frac{{{N_C}}}{{{N_V}}}} \right]\)

Q3.

The Fourier transform of the signal \( \ x(t)=e^{-at^2}\) , a > 0 will be

\(\sqrt{\frac{\pi}{\omega}}e^{\omega^2/2a}\)

\(\sqrt{\frac{\pi}{a}}e^{\omega^2/2a^2}\)

\(\sqrt{\frac{\pi}{a}}e^{-\omega^2/4a}\)

\(\sqrt{\frac{\pi}{\omega}}e^{-\omega^2/2a}\)

Q4.

If x(t) = e ^-tu(t) and y(t) = e ^-3tu(t), then y(t) * x(t) will be

(e ^-t– e ^-3t) u(t)

\(\frac{e^{-3t}-e^{-t}}{2}u(t)\)

\(\frac{e^{-t}-e^{-3t}}{2}u(t)\)

\(\frac{e^{-t}+e^{-3t}}{2}u(t)\)

Q5.

If density of states in conduction band and density of states in valence band are not equal, then the Fermi level in intrinsic semiconductor is

\(\frac{{{E_c} - {E_v}}}{2} + \frac{{{N_C} + {N_v}}}{2}\)

\(\frac{{{E_C} + {E_v}}}{2}\)

\(\frac{{{E_C} + {E_v}}}{2} - \frac{{kT}}{2}\ln \frac{{{N_C}}}{{{N_v}}}\)

\(\frac{{{E_C} + {E_v}}}{2} + \frac{{kT}}{2}\ln \frac{{{N_C}}}{{{N_v}}}\)

⋯

Page 1 of 20

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