JEE Main 2022 Question Paper (24-Jun-2022) (Shift 1)

Question 1

The bulk modulus of a liquid is $3 \times 10^{10} \, \mathrm{Nm}^{-2}$. The pressure required to reduce the volume of the liquid by $2\%$ is:

Accepted Answer

$6 	imes 10^{8} \quad \mathrm{N} \quad \mathrm{m}^{-2}$

Answer

$3 	imes 10^{8} \quad \mathrm{N} \quad \mathrm{m}^{-2}$

Answer

$9 	imes 10^{8} \quad \mathrm{N} \quad \mathrm{m}^{-2}$

Answer

$12 	imes 10^{8} \quad \mathrm{N} \quad \mathrm{m}^{-2}$

Question 2

Given below are two statements: One is labelled as Assertion (A) and the other is labelled as Reason (R). Assertion (A): In a uniform magnetic field, speed and energy remain the same for a moving charged particle. Reason (R): A moving charged particle experiences a magnetic force perpendicular to its direction of motion.

Accepted Answer

Both Assertion and Reason are true and Reason is the correct explanation of Assertion.

Answer

Both Assertion and Reason are true but Reason is NOT the correct explanation of Assertion.

Answer

Assertion is true but Reason is false.

Answer

Assertion is false but Reason is true.

Question 3

Two identical cells each of emf $1.5\mathrm{V}$ are connected in parallel across a parallel combination of two resistors each of resistance $20  \mathrm{\Omega}$. A voltmeter connected in the circuit measures $1.2  \mathrm{V}$. The internal resistance of each cell is :

Accepted Answer

$5 \quad \mathrm{\Omega}$

Answer

$2.5\quad \mathrm{\Omega}$

Answer

$4 \quad \mathrm{\Omega}$

Answer

$10 \quad \mathrm{\Omega}$

Question 4

Identify the pair of physical quantities which have different dimensions:

Accepted Answer

Specific heat capacity and Latent heat

Answer

Wave number and Rydberg's constant

Answer

Stress and Coefficient of Elasticity

Answer

Coercivity and Magnetisation

Question 5

A projectile is projected with a velocity of $25 \mathrm{m}  \mathrm{s}^{-1}$ at an angle $	heta$ with the horizontal. After $t$ seconds, its inclination with the horizontal becomes zero. If $R$ represents the horizontal range of the projectile, the value of $	heta$ will be:

Accepted Answer

${\cot}^{-1}\left(\frac{R}{20 t^{2}}\right)$

Answer

$\frac{1}{2} \sin^{-1}\left(\frac{5 t^{2}}{4 R}\right)$

Answer

$\frac{1}{2} \sin^{-1}\left(\frac{4R}{5 t^{2}}\right)$

Answer

${	an}^{-1}\left(\frac{4t^{2}}{5R}ight)$