JEE Main 2025 Question Paper (24-Jan-2025) (Shift 2)

Question 1

Based on the data given below: $ \begin{array}{cc} E^\circ_{\mathrm{Cr_2O_7^{2-}/Cr^{3+}}} = 1.33\, V & \quad E^\circ_{\mathrm{Cl_2/Cl^-}} = 1.36\, V \ E^\circ_{\mathrm{MnO_4^-/Mn^{2+}}} = 1.51\, V & \quad E^\circ_{\mathrm{Cr^{3+}/Cr}} = -0.74\, V \end{array} $ the strongest reducing agent is:

Accepted Answer

$Cr$

Answer

$ M^{n^{2+}} $

Answer

$ \mathrm{MnO}_{4}^{-} $

Answer

$Cl^{-}$

Question 2

Given below are two statements: In the light of the above statements, choose the correct answer from the options given below:

Accepted Answer

Statement I is true but Statement II is false

Answer

Both Statement I and Statement II are false

Answer

Statement I is false but Statement II is true

Answer

Both Statement I and Statement II are true

Question 3

For the reaction The correct order of set of reagents for the above conversion is:

Accepted Answer

$ \mathrm{H}_{2}\mathrm{SO}_{4},  \mathrm{Ac}_{2}\mathrm{O},  \mathrm{Br}_{2},  \mathrm{H}_{2}\mathrm{O}(\Delta),  \mathrm{NaOH} $

Answer

$ \mathrm{Br}_2 \mid  \mathrm{FeBr}_3, \mathrm{H}_2\mathrm{O}(\Delta),  \mathrm{NaOH} $

Answer

$ \mathrm{Ac}_2\mathrm{O},  \mathrm{Br}_2, \mathrm{H}_2\mathrm{O}(\Delta),  \mathrm{NaOH} $

Answer

$A c_{2} O, \; H_{2} SO_{4},  Br_{2},  NaOH$

Question 4

For hydrogen atom, the orbital/s with lowest energy is/are:(A) $4s$(B) $3p_x$(C) $3d_{x^2-y^2}$(D) $3d_{z^2}$(E) $4p_z$Choose the correct answer from the options given below:

Accepted Answer

(B), (C) and (D) only

Answer

(A) and (E) only

Answer

(B) only

Answer

(A) only

Question 5

In the given structure, the number of sp and sp2 hybridized carbon atoms present respectively are:

Accepted Answer

3 and 5

Answer

3 and 6

Answer

4 and 6

Answer

4 and 5