JEE Main 2019 Question Paper (12-Apr-2019) (Shift 1)

Question 1

The truth table for the circuit given in the figure is:

Accepted Answer

$ \left| \begin{array}{ccc} \mathrm{A} & \mathrm{B} & \mathrm{Y} \ 0 & 0 & 1 \ 0 & 1 & 1 \ 1 & 0 & 0 \ 1 & 1 & 0 \end{array} ight| $

Answer

$ \left| \begin{array}{ccc} \mathrm{A} & \mathrm{B} & \mathrm{Y} \ 0 & 0 & 0 \ 0 & 1 & 0 \ 1 & 0 & 1 \ 1 & 1 & 1 \end{array} ight| $

Answer

$ \left| \begin{array}{ccc} \mathrm{A} & \mathrm{B} & \mathrm{Y} \ 0 & 0 & 1 \ 0 & 1 & 0 \ 1 & 0 & 0 \ 1 & 1 & 0 \end{array} ight| $

Answer

$ \left| \begin{array}{ccc} \mathrm{A} & \mathrm{B} & \mathrm{Y} \ 0 & 0 & 1 \ 0 & 1 & 1 \ 1 & 0 & 1 \ 1 & 1 & 1 \end{array} ight| $

Question 2

The stopping potential $V_{0}$ (in volt) as a function of frequency $\left(v\right)$ for a sodium emitter is shown in the figure. The work function of sodium, from the data plotted in the figure, will be:
(Given: Planck’s constant $h = 6.63 \times 10^{-34} \,\mathrm{J\,s}$, electron charge $e = 1.6 \times 10^{-19} \,\mathrm{C}$)

Accepted Answer

$1.66 \quad \mathrm{eV}$

Answer

$2.12\quad \mathrm{eV}$

Answer

$1.82\ \mathrm{eV}$

Answer

$1.95 \quad \mathrm{eV}$

Question 3

A concave mirror has radius of curvature of $40\,\mathrm{cm}$. It is at the bottom of a glass that has water filled up to $5\,\mathrm{cm}$ (see figure). If a small particle is floating on the surface of water, its image as seen from directly above the glass is at a distance $d$ from the surface of water. The value of $d$ is close to: (Refractive index of water $=1.33$)

Accepted Answer

$8.8\ \mathrm{cm}$

Answer

$13.4\ \mathrm{cm}$

Answer

$6.7\,\mathrm{cm}$

Answer

$11.7\ \mathrm{cm}$

Question 4

Two moles of helium gas are mixed with three moles of hydrogen molecules (taken to be rigid). What is the molar specific heat of the mixture at constant volume? $\left(R = 8.3 \, \mathrm{J}/\mathrm{mol} \, \mathrm{K}\right)$

Accepted Answer

$17.4\ \mathrm{J}/\mathrm{mol}\ \mathrm{K}$

Answer

$19.7\ \mathrm{J}/\mathrm{mol}\ \mathrm{K}$

Answer

$15.7\ \mathrm{J}/\mathrm{mol}\ \mathrm{K}$

Answer

$21.6\ \mathrm{J}/\mathrm{mol}\ \mathrm{K}$

Question 5

The value of the numerical aperture of the objective lens of a microscope is $1.25$. If light of wavelength $5000 \ \overset{\circ}{\mathrm{A}}$ is used, the minimum separation between two points, to be seen as distinct, will be:

Accepted Answer

$0.24\quad \mathrm{\mu m}$

Answer

$0.48\quad \mathrm{\mu m}$

Answer

$0.38\quad \mathrm{\mu m}$

Answer

$0.12\quad \mathrm{\mu m}$