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JEE Main 2019 Question Paper with Solutions (09-Jan-2019) (Shift 1); Download PDF

JEE Main 2019 Question Paper with Solutions for Jan 9, 2019 Shift 1 is available here for PDF download and can also be attempted in a test format for practice. JEE Main Paper 1 (B.E./B.Tech) is conducted in CBT mode and includes Physics, Chemistry, and Mathematics.

Free
JEE Main 2019 Question Paper (09-Jan-2019) (Shift 1)
180 Minutes
90 Questions
360 Marks
English
Showing 1 - 5 of 30 questions
Page 1 of 6

Q1.

A particle is moving with a velocity \( \overrightarrow{v} = K \left( y \widehat{i} + x \widehat{j} \right), \) where \( K \) is a constant.
The general equation for its path is:

Q2.

A conducting circular loop made of a thin wire has area \(3.5 \times 10^{-2} \mathrm{m}^2\) and resistance \(10  \Omega\). It is placed perpendicular to a time-dependent magnetic field \(B(t) = (0.4  \mathrm{T}) \sin(50 \pi t)\). The field is uniform in space. Then the net charge flowing through the loop during \(t = 0  \mathrm{s}\) and \(t = 10  \mathrm{ms}\) is close to:

Q3.

A rod of length $L$ at room temperature and uniform cross-sectional area $A$ is made of a metal having a coefficient of linear expansion $\alpha \; /°C$. It is observed that an external compressive force $F$ applied at each end prevents any change in the length of the rod when its temperature rises by $\Delta T \; \mathrm{K}$. Young's modulus, $Y$, for this metal is:

Q4.

Three charges \( +Q, q, +Q \) are placed respectively, at distances \( 0, \frac{d}{2} \), and \( d \) from the origin, on the \( x \)-axis. If the net force experienced by \( +Q \), placed at \( x=0 \), is zero, then the value of \( q \) is:

Q5.

When the switch $S$ in the circuit shown is closed, then the value of current $i$ will be:

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