UGC NET Result 2020, Scorecard, Cutoff and Eligibility Certificate
Updated On -
Apr 7, 2020
Content Curator
NTA will release UGC NET Result 2020 on July 5, 2020. Candidates can download UGC NET Result for June 2020 Exam from the official website – ugcnet.nta.nic.in by logging in with their UGC NET Application Number, Date of birth or Password. The result is issued in the form of scorecard containing the marks scored in each paper of UGC NET 2020. NTA will also publish UGC NET 2020 Cutoff PDF for 81 subjects at its website soon after result declaration.
- For unbiased decision, scores are normalized to adjust the difficulty level of the question papers in multiple shifts
- UGC NET Provisional Answer Keys, candidates’ response sheets and question papers will be released on June 24, 2020.
- Candidates will be allowed to challenge the provisional answer keys in online mode by paying a fee of INR 1000 per question.
- The fees is refunded if the challenges are accepted by NTA.
- NTA will publish UGC NET June 2020 Final Answer Keys on June 30, 2020.
- NTA’s decision on the challenges will be final and the result is declared on the basis of final answer keys.
- A total of 10,34,872 candidates registered in UGC NET 2019 December session, 7,93,813 appeared and 60,147 exam takers qualified for eligibility for Assistant Professor only whereas 5,092 qualified for JRF & eligible for Assistant Professor.
Download UGC NET 2020 Cutoff PDF Here
How to Check UGC NET 2020 Result?
Follow the steps given below to download the UGC NET Result 2020.
Step 1: Visit the official website of UGC NET – ugcnet.nta.nic.in
Step 2: On the website, click on ‘ UGC NET Result 2020’ link.
Step 3: Enter UGC NET Application Number and Date Of Birth or Password.
Step 4: The result will be displayed on the screen in the form of scorecard.
Step 5: Candidates must download and print the result of UGC NET 2020 for future use.
Details Mentioned on UGC NET Scorecard
Following information will be displayed on Scorecard:
- Candidate’s Name
- UGC NET Hall Ticket Number
- Rank scored by the candidate
- Name of the paper for which the candidate appeared
- Marks secured in each paper
- Total marks
- Percentage & Percentile
UGC NET 2020 Result Calculation
- Around 6% of the candidates will qualify the exam for Assistant Professor.
- Total slots will be allocated to different categories as per the reservation policy of Government of India.
- In order to be considered for ‘both JRF and Assistant Professorship’ or ‘Assistant Professorship only’ posts, the candidates must have appeared in both the papers and secured atleast 40% in aggregate (35% for reserved categories) in the exam.
The number of candidates to be declared qualified in any subject for a particular category is derived as per the methodology illustrated below:
Example: Candidate appears for Economics subject
| No. of candidates to be declared qualified for eligibility for Assistant Professor in the subject ‘Economics’ for the SC category | No. of candidates belonging to SC category who secure at least 35% aggregate marks in both the papers taken together for ‘Economics’ x Total slots derived for SC category as per Step II ÷ Total number of candidates belonging to SC category over all subjects who secure at least 35% aggregate marks in both the papers taken together. |
The aggregate percentage of the two papers corresponding to the number of slots arrived at, will determine the qualifying cutoff for eligibility for the post of Assistant Professor ‘in ‘Economics’ for the SC category. Similar yardstick shall be employed for deriving the subject-wise qualifying cutoffs for all categories.
All candidates who had applied for both ‘Eligibility for JRF & Assistant Professor’ out of the total number of qualified candidates derived as per Step IV, shall constitute the consideration zone for JRF.
Downoad UGC NET Question Papers
Step VI: The total number slots available for awarding JRF is allocated among different categories as per te reservation policy of Government of India. The procedure for subjectwise cum category-wise allocation of JRF slots is illustrated below:
Example:
| Number of candidates to be declared qualified for Both JRF & Assistant Professor in the subject ‘Economics’ for the Scheduled Tribe (ST) category | Number of candidates belonging to ST category who have opted for JRF and have qualified for Eligibility for Assistant Professor Both in the subject ‘Economics’ (x) Total JRF slots available for ST category (÷) Total number of candidates belonging to ST category over all subjects who have opted for JRF and have qualified for Eligibility for Assistant Professor |
The aggregate percentage of the two paper scores corresponding to the number of JRF slots arrived at, will determine the qualifying cutoff for JRF in ‘Economics’ for the ST category. Check Exam Pattern
UGC NET 2020 Normalization Process
Normalization of the scores is based on Percentile method to calculate the result for the examination. Through normalization, the difficulty level of exam is adjusted thereby providing an unbiased score. The scores are allotted between 100 to 0 for each session of the exam. Through Normalization, raw scores are converted to Percentile.
Formula:
Finally, the raw scores are merged with percentile for both the sessions to calculate the final result.
UGC NET Result for Junior Research Fellowship (JRF)
After the above process, a separate cut off list is prepared for the students eligible for JRF. Below is the formula to calculate the score and thus the eligibility.
UGC NET 2020 Cutoff
- A separate category-wise and subject-wise merit list will be prepared for the candidates who would have obtained the qualifying percentile.
- Top 6% candidates from the merit list will be declared NET qualified for eligibility of Assistant professorship only.
- Among NET qualified candidates a separate merit list will be created for the award of JRF.
- Minimum marks that a candidate must score in UGC NET to qualify will be:
| Category | Paper I + Paper II |
|---|---|
| General/ EWS | 120 marks (40%) |
| OBC-NCL/PwD/SC/ST | 105 marks (35%) |
*The article might have information for the previous academic years, please refer the official website of the exam.